In the adjoining figure, a wedge is fixed to an elevator moving upwards with an acceleration a a. the elevator goes up with a uniform velocity v and the block does A block of mass m 1 is pushed towards the movable wedge of mass m 2 and height h, with a velocity v 0. Consider an ideal inductor (having no resistance) of inductance L which is connected to an ideal cell (no resistance) of emf E by closing the switch S at time t =0. A wedge of mass m is pushed with a speed v0 on a rough horizontal plane. The minimum value of v 0 for which the block will reach the top of the This video contains an excellent analysis to a rather hard problem: A mass resting on a wedge, which itself is free to slide on a horizontal plane. Similar questions Q. Here is my introduction to Lagrangian • Introduction to Lagrangian Mechanics Here is the same problem solved using work-energy and , , A small block of mass m is pushed towards a movable wedge of mass ηm and height h withinitial velocity u. A block of mass m is moving with speed v on a wedge of mass M which is placed upon a horizontal surface. A bead of mass m kept at the top of a smooth hemispherical wedge of mass M and radius R, is gently pushed towards right. Find the A wedge of mass $M$ rests on a rough horizontal surface with coefficient of static friction $\mu$. What is the minimum speed v, so that the block When the particle is given a gentle push, it begins to slide and the system starts moving, but since there are no external torques, the sum of the individual angular momenta for the particle and wedge must Let us consider a situation as above in which there is a block of mass $m$ moving with velocity $v$ in positive $x$ direction on a frictionless wedge as given above. The face of the wedge is a smooth plane inclined at an angle $ A small block of mass m is kept on a rough inclined surface of inclination θ fixed in an elevator. A block of mass m is stationary with respect to a wedge of mass M moving with uniform speed v on a horizontal surface. A block of mass m is pushed towards a movable wedge of mass nm and height h, with a velocity u. A block of mass 1kg is pushed on a movable wedge of mass 2kg and height h = 30cm with a velocity u = 6m/sec. At a later time t, the speed V of the wedge, the speed v of the particle and the angle β of Here is a block sliding down a movable wedge without friction. Before striking the wedge it travels 2m on a rough horizontal portion. The horizontal force applied on the wedge is: D 2gh Solution: If v is common velocity of the block and movable wedge, then applying the principle of conservation of linear momentum we get, mu+ 0 = (m+nm)v v = m(1+n)mu = 1+nu This infact, can be A particle of mass m slides down the face of the wedge, starting from rest. Find the work done by friction force on the block in t second. A block of mass m m is placed over the wedge. A small block of mass m lies on a frictionless wedge of mass M, which is pushed horizontally to the right by means of a constant force F. The angle of Initial condition can be shown in the figure below As mass m collides with wedge, let both wedge and mass move with speed v ′. Find the velocity of the triangular block when the small block reaches the bottom: Here is what I did: The final velocity(at the bottom)of the small block of mass m . All surfaces are smooth. As a result, the wedge slides due left. The maximum height climbed by the particle on the wedge is given by 𝟐 v 𝟐 𝟓 g. The angle of inclination θ of the pendulum is see full For the figure shown, block of mass m is released from the rest. Track A B is a circular track of radius R. What is the $F_ {external}$ on the block required to accelerate the mass and wedge at the rate to suspend the block at a point on The correct answer is Since frictional force acts on the block, its deceleration is μg. The minimum value of u for which the block reaches the So if you sit on the wedge you will see the block staying in contact with the wedge but with a greater acceleration downwards than before. At the top of the ramp, the block will only have potential There is no friction between the particle and the plane or between the particle and the wedge. A smooth wedge of mass M is pushed with an acceleration a => anθ and a block of mass m is projected down the slant with a velocity v relative to the wedge. The angle of friction between the wedge and horizontal plane is ϕ . Then, By applying linear momentum conservation, we have Initial A wedge of mass M is pushed with a speed v 0 on a rough horizontal plane. So in the frame of wedge, a pseudo force μmg acts on the block and it is inclined at angle θ = ϕ with vertical. So in the frame of wedge, a pseudo force μmg acts on the block and it is inclined at angle θ=ϕ with vertical. Find the distance of the wedge from initial position, when block m arrives at the bottom of the wedge. Plot the variation of current Hint : In this solution, we will use the law of conservation of momentum to determine the velocity of the block when it starts climbing the ramp.
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